A force of 100N pulls a box of weight 200N along a smooth horizontal surface (angle = 45)
Calculate the work done by the force.
A- in moving the box a distance of 25m along the horizontal.
B- against gravity.
C- against normal force.
I wanna see how it's solved please
12 000J
2457
To calculate the work done by a force, we use the formula:
Work = Force × Distance × Cos(angle)
A) Work done by the force in moving the box a distance of 25m along the horizontal:
Here, the force acting on the box is 100N, and the distance it is moved is 25m. Since the surface is smooth, there is no friction, and the angle between the force and the displacement of the box is 0 degrees. Therefore, the formula becomes:
Work = 100N × 25m × Cos(0°)
Cos(0°) = 1, as Cos(0°) = 1
Work = 100N × 25m × 1
Work = 2500J (Joules)
Therefore, the work done by the force in moving the box a distance of 25m along the horizontal is 2500 Joules.
B) Work done against gravity:
The weight of the box is 200N, which is acting vertically downward. The force is pulling the box along the horizontal surface, so it is perpendicular to the force of gravity. Therefore, the angle between the force and the displacement of the box is 90 degrees.
Work = 100N × 25m × Cos(90°)
Cos(90°) = 0, as Cos(90°) = 0
Work = 100N × 25m × 0
Work = 0J (Joules)
Since the angle between the force and the displacement is 90 degrees (perpendicular), no work is done in moving the box against gravity.
C) Work done against the normal force:
The normal force is perpendicular to the force applied, so the angle between the force and the displacement of the box is also 90 degrees.
Work = 100N × 25m × Cos(90°)
Cos(90°) = 0, as Cos(90°) = 0
Work = 100N × 25m × 0
Work = 0J (Joules)
Similar to the work done against gravity, no work is done against the normal force as well.