chemistry
posted by bubble on .
The Rydberg equation (1/lambda=R/ni^2–R/nf^2) can be treated as a line equation. What is the value of nf as a function of the slope (m) and yintercept(b)?
by GC 1/lambda = R/ni^2–R/nf^2
y = mx + b (standard form) of a linear equation)
x = (yb)/m
Let,
y = 1/lambda
m = R
x = 1/nf^2
b = R/ni^2
1/nf^2 = [(1/lamda)(R/ni^2)]/(R)
Solve for nf
i still don't get how you get rid of y and x to get m and b in the end

Answer is (m/b)^1/2

I don't know the answer to this question but I put the answer given above is wrong if you are doing the uci webwork from chem 1LB

dude its (M/B)^(1/2)

im doing uci webwork and that's right
(M/B)^(1/2) 
Alex Le and bowisha
you're all probably stupid in school
thats y u want to let people down idiots
answer is correct as mb to the 1/2
not negative
this is the Right answer 
I'm doing the webwork for uci, not sure what the answer is but it's not (m/b)^1/2. thanks people....

it's negative

yo it is (m/b)^(1/2) i just did it and submitted.