Posted by bubble on Friday, January 15, 2010 at 2:16am.
The Rydberg equation (1/lambda=R/ni^2–R/nf^2) can be treated as a line equation. What is the value of nf as a function of the slope (m) and yintercept(b)?
by GC 1/lambda = R/ni^2–R/nf^2
y = mx + b (standard form) of a linear equation)
x = (yb)/m
Let,
y = 1/lambda
m = R
x = 1/nf^2
b = R/ni^2
1/nf^2 = [(1/lamda)(R/ni^2)]/(R)
Solve for nf
i still don't get how you get rid of y and x to get m and b in the end

chemistry  UCI CHEM1B, Friday, January 15, 2010 at 5:39am
Answer is (m/b)^1/2

chemistry  zot!, Saturday, January 16, 2010 at 9:23pm
I don't know the answer to this question but I put the answer given above is wrong if you are doing the uci webwork from chem 1LB

Chem1LB  Alex Le, Sunday, January 17, 2010 at 2:06am
dude its (M/B)^(1/2)

chemistry  bowisha, Sunday, January 17, 2010 at 5:22pm
im doing uci webwork and that's right
(M/B)^(1/2)

chemistry  jolie, Sunday, January 17, 2010 at 8:08pm
Alex Le and bowisha
you're all probably stupid in school
thats y u want to let people down idiots
answer is correct as mb to the 1/2
not negative
this is the Right answer

chemistry  wow, Sunday, January 17, 2010 at 10:36pm
I'm doing the webwork for uci, not sure what the answer is but it's not (m/b)^1/2. thanks people....

chemistry  wow.., Monday, January 18, 2010 at 2:28am
it's negative

chemistry  Antonio, Monday, January 18, 2010 at 4:23pm
yo it is (m/b)^(1/2) i just did it and submitted.
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