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February 1, 2015

February 1, 2015

Posted by **George** on Friday, January 15, 2010 at 1:03am.

- Find all solutions in the interval [0, 2pi)

I got pi/2 but the answer says {0, pi/2, pi}

Where does 0 and pi come from for solutions? When simplifying I just get sin(x)=1

- Pre-Calculus -
**Damon**, Friday, January 15, 2010 at 3:47amIf x = 0

cos^2 0 = 1 and sin 0 = 0 and 1+0 =1

If x = pi

cos^2 pi = (-1)(-1) = 1 and sin pi = 0 so 1+0 = 1 again

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