How do you find the H-Shift.
My problem is y=5 sin(3x-pi/2).
Do you mean horizontal shift?
Look at this:
(3x-PI/2)= 3(x-PI/6)
see the PI/6 term?
Do you mean where does the function cross the x axis first after x = 0?
If so it is when
3x-pi/2 = 0
or
x = pi/6
yes I meant horizontal shift. so PI/6 is the answer?
Jennifer, graph it starting at x = 0 and go to x = pi/3
see where it crosses the axis
then what's the ending point?
It is a sine function. It goes on and on forever. The shift is just how much it is offset from the origin by being sin(3x-pi/2) instead of being sin(3x)
never mind. I get it.
atta go :)
To find the H-shift in the equation y = 5 sin(3x - π/2), you need to look at the parentheses inside the sin function. The general form of a sinusoidal function is y = a sin(b(x - h)) + k, where h represents the H-shift.
In this case, the expression inside the sin function is 3x - π/2. To isolate the x-variable, you can set the expression equal to zero and solve for x.
3x - π/2 = 0
Next, you want to solve for x:
3x = π/2
x = π/6
So, the H-shift in the equation y = 5 sin(3x - π/2) is π/6 units to the right.