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March 29, 2017

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A square is drawn inside a square. Find the area of the square as a function of the radius of the circle.

  • pre calc - ,

    The diameter of the circle is 2*Radius

    area of square= diameter^2= 4 * R^2

  • pre calc - ,

    so that is the answer

  • pre calc - ,

    No, the diameter of the circle is the diagonal of the square
    Side of square = D/sqrt2
    Area of square = D^2/2
    but D = 2 R
    so
    area of square = 4 R^2/2 = 2 R^2

  • pre calc - ,

    which one is the correct answer

  • pre calc - ,

    Draw a graph. Start at x = 0 and work your way up to x = pi/6

  • pre calc - ,

    Oh, sorry, worong question. Draw your square inside the circle and you will see that the diagonal of the square is the diameter of the circle.
    The diagonal of the square divides the square into two 45,45,90 triangles
    The hypotenuse of a 45,45,90 triangle id the side times sqrt 2
    s^2+s^2 = diagonal^2
    2 s^2 = diagonal^2
    s = (1/sqrt2) diagonal
    so
    diagonal = side * sqrt 2 = diameter

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