Thursday

December 18, 2014

December 18, 2014

Posted by **JJ** on Thursday, January 14, 2010 at 4:33pm.

Calculate the change in pressure between the wide and narrow regions of the pipe. Give your answer as an expression in terms of the density of water, rho, and initial speed v.

- physics -
**drwls**, Thursday, January 14, 2010 at 4:38pmThe incompressible continuity equation

(Area)*(velocity) = constant

tells you that the speed is 1/4 as high in the wider section. Thus v' = v/4 is the new velocity.

Use the Bernoulli equation to complete the problem. The pressure increase equals the decrease in (1/2)(rho)V^2

Show your work if you need additional assistance.

**Answer this Question**

**Related Questions**

Physics - Water flows at 12 m/s in a horizontal pipe with a pressure of 3.0 x 10...

Physics - Water flows under pressure from one pipe into a second pipe having ...

Physics - A liquid of density 1.23 × 103 kg/m3 flows steadily through a pipe of ...

physic - Water flows through a 4.0-cm-diameler horizontal pipe ata speed uf 1.3 ...

physics - A horizontal pipe 17.00 cm in diameter has a smooth reduction to a ...

physics - A horizontal pipe 17.00 cm in diameter has a smooth reduction to a ...

Physics - A horizontal pipe, 10 cm in diameter, has a smooth reduction to a pipe...

physics - What is the pressure change in water going from a 3.0- cm-diameter ...

Fluid Mechanics - Water flows into a cylindrical tank through pipe 1 at a rate ...

physics - 1.)Water flows from a 2 cm diameter pipe, at a speed of 0.35m/sec. How...