Precal
posted by Joe on .
I do not understand how to do this problem
((sin^3 A + cos^3 A)/(sin A + cos A) ) = 1  sin A cos A
note that all the trig terms are closed right after there A's
example
sin A cos A
=
sin (A) cos (A)
I wrote it out like this
0 =  sin^6 A  cos^6 A + 2sin^3 A cos^3 A  2sin^3 A  3sin^2 A cos^2 A  2sinA cosA + 1
I graphed the problem and my solution and got the same line so my questio is how do i simplify thank you????

use graphic techiques in radians I found that it is roughly equal to
.5 sin [ 20.42036^1(x + 40.84071)pi ] + 1 
that didn't get me any were lol