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August 31, 2014

August 31, 2014

Posted by **Joe** on Thursday, January 14, 2010 at 1:43pm.

((sin^3 A + cos^3 A)/(sin A + cos A) ) = 1 - sin A cos A

note that all the trig terms are closed right after there A's

example

sin A cos A

=

sin (A) cos (A)

I wrote it out like this

0 = - sin^6 A - cos^6 A + 2sin^3 A cos^3 A - 2sin^3 A - 3sin^2 A cos^2 A - 2sinA cosA + 1

I graphed the problem and my solution and got the same line so my questio is how do i simplify thank you????

- Precal -
**Joe**, Thursday, January 14, 2010 at 1:50pmuse graphic techiques in radians I found that it is roughly equal to

-.5 sin [ 20.42036^-1(x + 40.84071)pi ] + 1

- STILL NEED HELP -
**STILL NEED HELP**, Thursday, January 14, 2010 at 1:51pmthat didn't get me any were lol

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