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November 28, 2014

November 28, 2014

Posted by **Andrea** on Thursday, January 14, 2010 at 11:41am.

- physics -
**drwls**, Thursday, January 14, 2010 at 1:29pmSince the stone start with no initial vertical velocity component, the time T to hit the water is given by

H = 52 m = (1/2) g T^2

which leads to

T = sqrt(2H/g)

The speed V2 when it hits the surface is most easily computed using energy conservation.

(1/2) m V2^2 = (1/2) m V1^2 + m g H

V2^2 = V1^2 + 2gH

V1 is the initial velocity, 18 m/s.

You know what g is, I assume.

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