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December 18, 2014

December 18, 2014

Posted by **Bri** on Wednesday, January 13, 2010 at 6:55pm.

- PreCalculus -
**drwls**, Wednesday, January 13, 2010 at 7:54pmLet the length of the side parallel to the wall be x. The two perpendicular sides will then each be y in length.

Solve this pair of equations:

x + 2y = 160

x y = 2800

(160-2y)y = 2800

-2y^2 +160y = 2800

y^2 -80y +1400 = 0

Solve for y or factor. It looks to me like the answer is not an integer, there may be two solutions. Use the quadratic equation.

y = [80 + sqrt(800)]/2

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