Posted by **Bri** on Wednesday, January 13, 2010 at 6:55pm.

Three sides of a fence and an existing wall form a rectangular enclosure. The total length of a fence used for the three sides is 160 feet. Find the value(s) for which the area is 2800 square feet.

- PreCalculus -
**drwls**, Wednesday, January 13, 2010 at 7:54pm
Let the length of the side parallel to the wall be x. The two perpendicular sides will then each be y in length.

Solve this pair of equations:

x + 2y = 160

x y = 2800

(160-2y)y = 2800

-2y^2 +160y = 2800

y^2 -80y +1400 = 0

Solve for y or factor. It looks to me like the answer is not an integer, there may be two solutions. Use the quadratic equation.

y = [80 + sqrt(800)]/2

## Answer this Question

## Related Questions

Math Calculus - Three sides of a fence and an existing wall form a rectangular ...

math - Ex. 120 m of fencing is to be used to form three sides of a rectangular ...

Algebra - A builder has 80 feet of fencing to create an enclosure adjacent to a ...

Help with maths! - A rectangular field is surrounded by a fence on three of its ...

Pre-calc - a rectangular yard is to be enclosed by a new fence on 3 sides and by...

Pre-calc - a rectangular yard is to be enclosed by a new fence on 3 sides and by...

Calculus - The owner of a used tire store wants to construct a fence to enclose ...

calculus (optimization) - a rectangular study area is to be enclosed by a fence ...

Math - A rectangular study area is to be enclosed by a fence and divided into ...

Calculus - A fence is to be built to enclose a rectangular area of 280 square ...