I need to figure out what a deposit of 3500 a month, with 9 percent intrest compounded monthly, would be in 6 years. Any help would be greatly appreciated.

$3500 * (1.0075)^72 = $5,993.93

The balance is increased by a factor
1 + (0.09/12), each month for 72 months.

Determine the number of months required for a deposit of $3500 to earn $262.75 simple interest at 7.35%

To calculate the future value of a deposit with compound interest, you can use the formula for compound interest:

A = P(1 + r/n)^(nt)

Where:
A is the future value of the deposit
P is the initial amount (the deposit)
r is the annual interest rate (as a decimal)
n is the number of times the interest is compounded per year
t is the number of years

In this case, the deposit is $3500 per month, so the initial amount (P) is $3500. The annual interest rate (r) is 9 percent, which needs to be converted to a decimal, so r = 0.09. The interest is compounded monthly, so n = 12. Finally, you want to find the future value in 6 years, so t = 6.

Substituting these values into the formula, we get:

A = 3500(1 + 0.09/12)^(12*6)

Now let's evaluate the expression step by step:

1. Calculate the value inside the parentheses:
0.09/12 = 0.0075

2. Add 1 to the result:
1 + 0.0075 = 1.0075

3. Calculate the exponent (12*6 = 72):
1.0075^72 ≈ 1.759

4. Multiply the initial deposit by the result:
3500 * 1.759 ≈ $6,156.50

Therefore, after 6 years, a deposit of $3500 per month with a 9% interest rate compounded monthly will amount to approximately $6,156.50.