Solve the equation. Check the equation.
c= square root of(3c-8)
Please Help!!!! Thanks.
c = sqrt(3c-8)
Square both sides.
c^2 = 3c - 8
From here the problem is simple.
I'm sorry but could you please check my answer: (3+4i�ã7/2) and (3-4i�ã7/2).
Also, how would I check my answer?
To solve the equation c = √(3c-8), you need to isolate the variable c on one side of the equation. Here's how you can solve it step by step:
1. Start by squaring both sides of the equation to eliminate the square root:
c^2 = (3c - 8)
2. Expand the right side of the equation:
c^2 = 3c - 8
3. Rearrange the equation so that it is a quadratic equation in standard form:
c^2 - 3c + 8 = 0
Now we have a quadratic equation that we can solve using factoring, completing the square, or the quadratic formula. In this case, the quadratic equation cannot be easily factored, so we will use the quadratic formula:
The quadratic formula is given by:
c = (-b ± √(b^2 - 4ac)) / (2a)
In our quadratic equation, a = 1, b = -3, and c = 8. Substituting these values into the quadratic formula:
c = (-(-3) ± √((-3)^2 - 4(1)(8))) / (2(1))
Simplifying further:
c = (3 ± √(9 - 32)) / 2
c = (3 ± √(-23)) / 2
Since the term inside the square root is negative (-23), the equation has no real solutions. Hence, there are no real values of c that satisfy the equation c = √(3c-8).
To check, you can substitute the possible solutions back into the original equation and verify if they hold true. However, in this case, there are no solutions to check as there are no real solutions for c.