Posted by jen on Tuesday, January 12, 2010 at 2:32pm.
Here the integral is being evaluated, so the area of the elementary figures could be positive or negative.
It can be observed that all the line segments form a (twisted) trapezoid with the x-axis, i.e. part of the area is above the x-axis, and part of it is below.
Knowing that the area of a trapezoid is the average of the y-coordinate of the two ends, multiplied by the length, it will be possible to calculate the three areas separately.
For example, the area created by the segment AB is:
Average of y-coordinates = (2+(-3))/2=-0.5
Length = (1-(-2)) =3
Integral of segment AB=3*(-0.5) = -1.5
Repeat for the two other segments and add up the total.
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