Posted by **Diana** on Monday, January 11, 2010 at 11:22pm.

Solve the equation for x in the interval 0<x<2pi

1/ 1+tan^2x = -cos x

How would i do this? im thinking of maybe changing the 1+tan to sec^2x?

## Answer this Question

## Related Questions

- Integration - Intergrate ¡ì sec^3(x) dx could anybody please check this answer. ...
- Trigonometry desperate help, clueless girl here - 2. solve cos 2x-3sin x cos 2x...
- Trigonometry - 1.Solve tan^2x + tan x – 1 = 0 for the principal value(s) to two ...
- Trig - Solve the equation on the interval 0 less than or equal 0 < 2pi. 1. ...
- Trig. - sec^2xcotx-cotx=tanx (1/cos)^2 times (1/tan)-(1/tan)=tan (1/cos^2) times...
- precalculus - For each of the following determine whether or not it is an ...
- Trig - Given: cos u = 3/5; 0 < u < pi/2 cos v = 5/13; 3pi/2 < v < ...
- math - Solve the equation in the interval [0,2pi]. List all solutions tan^2(x)+0...
- trig - please help me with some questions I skipped on a review for our test ...
- trigonometry hlp me - 6.Prove that tan y cos^2 y + sin^2y/sin y = cos y + sin y...

More Related Questions