Posted by **lupe** on Monday, January 11, 2010 at 10:06pm.

Water flows at 12 m/s in a horizontal pipe with a pressure of 3.0 x 10 4 N/m2 . If the pipe widens to twice its original radius, what is the pressure in the wider section?

- Physics -
**drwls**, Monday, January 11, 2010 at 10:36pm
The water speed will drop by a factor 1/4 because of the larger pipe area. That follows from the incompressible fluid continuity equation, V * Area = constant. The water speed in the wider section is 3 m/s

Use the change in velocity and the Bernoulli equation to get the change in pressure.

P + (1/2)(density) V^2 = constant

P2 - P1 = (1/2)(water density)(V1^2 - V2^2

Solve for P2.

- Physics -
**Anonymous**, Wednesday, April 15, 2015 at 9:49pm
xas

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