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A Van de Graaff generator is charged so that the magnitude of the electric field at its surface is 3.0 multiplied by 104 N/C.
(a) What is the magnitude of the electric force on a proton released at the surface of the generator?

(b) Find the proton's acceleration at this instant.

  • math/physics -

    Force= Eq, right?
    solve, you know the charge of a proton.

    F=ma solve for a.

  • math/physics -

    a) Force = E*e
    where E is the field in N/C and e is the electron (and proton) charge,
    1.6*10^-19 C

    b) acceleration = Force/(proton mass)

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