Posted by **asia** on Monday, January 11, 2010 at 9:43pm.

A 1100 kg car rolling on a horizontal surface has speed v = 70 km/h when it strikes a horizontal coiled spring and is brought to rest in a distance of 2.2 m. What is the spring stiffness constant of the spring?

- physics -
**drwls**, Monday, January 11, 2010 at 10:05pm
The car comes to rest (temporarily)at compression distance X, at which point the initial kiteci energy (1/2) M V^2 is converted to spring potential energt, (1/2)kX^2.

Therefore

kX^2 = mV^2

k = m (V/X)^2

Make sure you convert V to meters per second before using the formula. k will be in Newtons/meter

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