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Math-gr12

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How would I solve this equation for x in the interval 0<x<2pi

tan^2x sinx - sinx/3 = 0

Please explain it step by step..ive been stuck on this question for far too long..sigh

  • Math-gr12 - ,

    Try factoring out sin(x).

  • Math-gr12 - ,

    how would i do that?

  • Math-gr12 - ,

    tan^2(x)*sin(x)-sin(x)/3 = 0

    can be rewritten as

    sin(x) [ tan^2(x) - 1/3] = 0

    which is solvable.

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