Thursday
March 23, 2017

Post a New Question

Posted by on Monday, January 11, 2010 at 8:29pm.

I'm stumped again :(
the question is - A gas sprayed from an aerosol can effuses 5.06 times slower than oxygen.If the molar mass of oxygen is 32.g/mol, what is the molar mass of the unknown gas?

I don't know if I am doing the ideal gas law or grahams law or how to set it up. Please help. Thanks

  • chemistry - , Monday, January 11, 2010 at 8:46pm

    Graham's Law is what you want.
    rate 1/rate 2 = (sqrt molar mass 2/sqrt molar mass 1)

  • chemistry - , Monday, January 11, 2010 at 8:49pm

    so what would be rate 1 and 2?

  • chemistry - , Monday, January 11, 2010 at 9:06pm

    Make up a number for the rate of the unknown gas. Then oxygen will be 5.06 times less than that.

Answer This Question

First Name:
School Subject:
Answer:

Related Questions

More Related Questions

Post a New Question