-3/4z-2/3=1/3
I've answered a couple for you. Now it's your turn. How do you think this problem should be solved?
3(q+1)-9=23
3q *3-9=23
3q*3 -9+9=23+9
I am not sure what to do with the 3 I think that I am suppose to add 23+9 on the right side. this is where I get confused.
Two of us have already solved this problem for you. See below.
To solve the equation -3/4z - 2/3 = 1/3, follow these steps:
Step 1: Remove the fractions by multiplying each term in the equation by the least common multiple (LCM) of the denominators, which in this case is 12. This will eliminate the fractions.
Multiply -3/4z by 12: (-3/4) * 12 = -9z
Multiply -2/3 by 12: (-2/3) * 12 = -8
After multiplying both terms by 12, the equation becomes:
-9z - 8 = 4
Step 2: Isolate the variable term by performing inverse operations in order to move the constant term to the other side of the equation.
Add 8 to both sides of the equation:
-9z - 8 + 8 = 4 + 8
-9z = 12
Step 3: Solve for z by dividing both sides of the equation by the coefficient of z, which is -9.
Divide both sides by -9:
-9z / -9 = 12 / -9
z = -4/3
Therefore, the solution to the equation -3/4z - 2/3 = 1/3 is z = -4/3.