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September 30, 2014

September 30, 2014

Posted by **Sally** on Monday, January 11, 2010 at 5:50pm.

- physics -
**Damon**, Monday, January 11, 2010 at 6:19pmFirst find East component of each

15 cos 45 - 30

Now find south component of each

15 sin 45 + 0

so

East = -19.4 or 19.4 West resultant

South = 10.6

tangent of angle south of West (quadrant 3) = 10.6/19.4 = .547

tan^-1 .547 = 28.7 degrees South of West

magnitude = sqrt (19.4^2+10.6^2)

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