Posted by A on Sunday, January 10, 2010 at 9:34pm.
1. Place an arrow at the appropriate spot so you can tell the reactants from the products.
2. Convert 0.333 g Al to moles. moles = g/molar mass. Convert 0.501 g I2 to moles.
3a. Using the coefficients in the balanced equation, convert moles Al to moles AlI3.
3b. Using the same procedure, convert moles I2 to moles AlI3.
3c. The smaller number from 3a versus 3b is the limiting reagent AND is the correct value for the number of moles AlI3 formed.
For the second part, using the limiting reagent, go through the same kind of procedure to determine how much of the OTHER reagent is needed to react with the limiting reagent, then subtract that amount from the initial amount to determine how much remains un-reacted.
Post your work if you get stuck.
Related Questions
Chemistry - If 430 mL of 0.837 M aqueous HNO3 and 23.5 g of solid Al are reacted...
Chemistry - Based on the following chemical equation answer the question below ...
chemistry - Based on the following chemical equation, answer the questions below...
Chemistry - Assume that 7.2 L of I2 are produced at STP according to the ...
Chemistry - Assume that 7.2 L of I2 are produced at STP according to the ...
Chemistry - Assume that 7.2 L of I2 are produced at STP according to the ...
chem - Anhydrous aluminum oxide can be reduced to aluminum according to thisa ...
chemistry - Assume that 7.2 L of I2 are produced at STP according to the ...
college chemistry - please help! If the initial pressure of I2(g) is 1.738 atm, ...
Chemistry - Al+S=Al2S3 Balanced equ= 2Al+3S=Al2S3 10 grams of Al were mixed ...
For Further Reading
