How many grams of oxygen can be produced from the decomposition of 100g of KClO3?
and can you please explain the process resulting with the answer (ie. formulas ect.) thank you.
thx
To determine the number of grams of oxygen produced from the decomposition of KClO3, you need to know the molar mass of KClO3 and perform a stoichiometric calculation.
Step 1: Find the molar mass of KClO3
- The molar mass of potassium (K) is 39.10 g/mol.
- The molar mass of chlorine (Cl) is 35.45 g/mol.
- The molar mass of oxygen (O) is 16.00 g/mol.
- Now, calculate the molar mass of KClO3:
Molar mass of KClO3 = (39.10 g/mol) + (35.45 g/mol) + (3 * 16.00 g/mol)
= 122.55 g/mol
Step 2: Set up the stoichiometric equation.
The balanced equation for the decomposition of KClO3 is:
2 KClO3 → 2 KCl + 3 O2
Step 3: Use stoichiometry to find the number of moles of O2 produced.
Since we know that 2 moles of KClO3 decompose to produce 3 moles of O2, we can set up a ratio:
(3 mol O2 / 2 mol KClO3)
Step 4: Convert grams of KClO3 to moles.
Using the molar mass of KClO3, we can convert the given 100 grams of KClO3 to moles using the following ratio:
(100 g KClO3 * (1 mol KClO3 / 122.55 g KClO3))
Step 5: Calculate the number of moles of O2.
Multiply the moles of KClO3 by the stoichiometric ratio from step 3:
(moles of O2 = moles of KClO3 * (3 mol O2 / 2 mol KClO3))
Step 6: Convert moles of O2 to grams.
Since the molar mass of oxygen is 16.00 g/mol, we can convert the moles of O2 to grams using the following ratio:
(grams of O2 = moles of O2 * 16.00 g/mol)
By following these steps, you can determine the grams of oxygen produced from the decomposition of 100g of KClO3.
I love men.
how many moles of KClO3 do you have in 100 g.
2) balance the equation:
2KClO3>>2K + Cl2 + 3O2
so for every two moles of potassium chlorate, you get three moles of O2
3) take the moles of KClO3, multiply it by 3/2. That is the moles of KClO3. Convert it to grams.