Wednesday
October 22, 2014

Homework Help: Trig.

Posted by Tara on Sunday, January 10, 2010 at 12:31pm.

Can you please review this to see if I did this right?

2cos^2x+3cosx=0

sq. root of (cos^2x)+(cosx)=sq. root of (-3/2)

2cos=(sq. root of -3 times sq. root of 2)/2)) times 2/1

cos=(2 times sq. root of -3 times sq. root of two)/2))

Answer this Question

First Name:
School Subject:
Answer:

Related Questions

Math - Solving for Trig Equations - Solve the following equation for 0 less than...
Algebra - I had to solve 2x^2-x-1 using the quad. formula. I got it down to (1...
Algebra - Can you explain how to find the solution of 3x^2-2x+5, using the ...
Trig. - sec^2xcotx-cotx=tanx (1/cos)^2 times (1/tan)-(1/tan)=tan (1/cos^2) times...
Math - Just need some help... Directions: Multiply or raise to the power as ...
Math simplifying mixed radicals - Please help me simplify these following mixed ...
math - What does it mean to have the sqaure root of 5 with a 2 in front of it? ...
Math - I don't get how you get these answers: cos180 degree = -1 sin45 degree = ...
Algebra - Rationalize each expression by building perfect nth root factors for ...
Calculus - Hello Everyone, I need help with Calc II. 1. Integral from 0 to 1 of...

Search
Members