Saturday

January 31, 2015

January 31, 2015

Posted by **Tara** on Sunday, January 10, 2010 at 12:31pm.

2cos^2x+3cosx=0

sq. root of (cos^2x)+(cosx)=sq. root of (-3/2)

2cos=(sq. root of -3 times sq. root of 2)/2)) times 2/1

cos=(2 times sq. root of -3 times sq. root of two)/2))

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