Posted by Please on Saturday, January 9, 2010 at 6:06pm.
The distance between the trains decreases at a rate of 50 - 40 = 10 mph = 1/6 mile per minute.
At 8:27 PM, train A is (1/6 h) * 40 miles/h = 40/6 miles ahead of B.
The 40/6 mile gap between trains will become zero after
t = (40/6 mile)/(1/6 mile/minute)
= 40 minutes
so they will meet up at 9:07 am?
Yes
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