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November 29, 2014

November 29, 2014

Posted by **Please** on Saturday, January 9, 2010 at 6:06pm.

I know this is a distant rate a time question but cannot seem to write out the correct formula and arrive at a correct answer.

- math/story problem -
**drwls**, Saturday, January 9, 2010 at 7:03pmThe distance between the trains decreases at a rate of 50 - 40 = 10 mph = 1/6 mile per minute.

At 8:27 PM, train A is (1/6 h) * 40 miles/h = 40/6 miles ahead of B.

The 40/6 mile gap between trains will become zero after

t = (40/6 mile)/(1/6 mile/minute)

= 40 minutes

- math/story problem -
**lisa**, Saturday, January 9, 2010 at 7:08pmso they will meet up at 9:07 am?

- math/story problem -
**drwls**, Saturday, January 9, 2010 at 10:57pmYes

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