A supersoaker water pistol can hold up to 4 litres of water. If each shot uses 11/12 of amount of water of its previous shot, the amount of water fired by a fully loaded supersoaker's first shot is?

x/4000ml=11/12
x=3666.7mL

why is the answer 333mL?

This is an infinite geometric series and the sum of the series is one liter

Sum = 1000 mL = g/(1-r) where r=11/12 and g is the first term, what we want.
so
1000 = g/(1/12)
g = 1000/12 = 83.33 mL

oh, sorry, 4 liters not one

times 4
83.33*4 = 333.3333.... mL

To find the amount of water fired by the fully loaded supersoaker's first shot, we need to determine how much water is left after each successive shot.

The problem states that each shot uses 11/12 of the amount of water used in the previous shot. Therefore, if the supersoaker is initially fully loaded with 4 liters of water, the amount of water fired by the first shot is (11/12) * 4 liters.

To solve this, we can first convert 4 liters to milliliters, as follows:
4 liters = 4000 milliliters

Now, we can calculate the amount of water fired by the first shot:
(11/12) * 4000 milliliters = 3666.7 milliliters (rounded to one decimal place)

So, according to the calculations, the amount of water fired by the fully loaded supersoaker's first shot is approximately 3666.7 milliliters, not 333 milliliters.

If you obtained an answer of 333 milliliters, there might have been an error in the calculations or rounding.