A supersoaker water pistol can hold up to 4 litres of water. If each shot uses 11/12 of amount of water of its previous shot, the amount of water fired by a fully loaded supersoaker's first shot is?
why is the answer 333mL?
This is an infinite geometric series and the sum of the series is one liter
Sum = 1000 mL = g/(1-r) where r=11/12 and g is the first term, what we want.
1000 = g/(1/12)
g = 1000/12 = 83.33 mL
oh, sorry, 4 liters not one
83.33*4 = 333.3333.... mL