Posted by cyn on Saturday, January 9, 2010 at 5:17pm.
A supersoaker water pistol can hold up to 4 litres of water. If each shot uses 11/12 of amount of water of its previous shot, the amount of water fired by a fully loaded supersoaker's first shot is?
x/4000ml=11/12
x=3666.7mL
why is the answer 333mL?

math  Damon, Saturday, January 9, 2010 at 5:32pm
This is an infinite geometric series and the sum of the series is one liter
Sum = 1000 mL = g/(1r) where r=11/12 and g is the first term, what we want.
so
1000 = g/(1/12)
g = 1000/12 = 83.33 mL

math  Damon, Saturday, January 9, 2010 at 5:35pm
oh, sorry, 4 liters not one
times 4
83.33*4 = 333.3333.... mL
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