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October 30, 2014

October 30, 2014

Posted by **Tara** on Saturday, January 9, 2010 at 10:40am.

3tan^2u=1

tan^2u=1/3

sq. root of (tan^2u)=sq. root of (1/3)

tanu=sq. root of (3)/3

tanu=sq. root of 1

Did I do this one right? If not, could you please show me the correct method??

Thanks!

- Trig -
**drwls**, Saturday, January 9, 2010 at 11:24amI don't understand your last step.

From tanu=sq. root of (3)/3

The next step would be

u = tan^-1[1/(sqrt3)]= 30 degrees

(or 210 degrees)

Your first steps are OK, until the last line.

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