Trig
posted by Tara .
4tan^2u1=tan^2u
3tan^2u=1
tan^2u=1/3
sq. root of (tan^2u)=sq. root of (1/3)
tanu=sq. root of (3)/3
tanu=sq. root of 1
Did I do this one right? If not, could you please show me the correct method??
Thanks!

I don't understand your last step.
From tanu=sq. root of (3)/3
The next step would be
u = tan^1[1/(sqrt3)]= 30 degrees
(or 210 degrees)
Your first steps are OK, until the last line.