sq. root of (tan^2u)=sq. root of (1/3)
tanu=sq. root of (3)/3
tanu=sq. root of 1
Did I do this one right? If not, could you please show me the correct method??
Trig - drwls, Saturday, January 9, 2010 at 11:24am
I don't understand your last step.
From tanu=sq. root of (3)/3
The next step would be
u = tan^-1[1/(sqrt3)]= 30 degrees
(or 210 degrees)
Your first steps are OK, until the last line.