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August 30, 2015

Homework Help: Trig.

Posted by Trig on Saturday, January 9, 2010 at 10:27am.

sec^2xcotx-cotx=tanx

(1/cos)^2 times (1/tan)-(1/tan)=tan

(1/cos^2) times (-2/tan)=tan

(-2/cos^2tan)times tan=tan(tan)

sq. root of (-2/cos^2)= sq. root of (tan^2)

sq. root of (2i)/cos=tan

I'm not sure if I did this right. If I didn't, can you show me the correct steps?

Thanks, I appreciate it.

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