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March 27, 2015

March 27, 2015

Posted by **BJ** on Friday, January 8, 2010 at 5:05pm.

- Physics -
**drwls**, Friday, January 8, 2010 at 6:11pmFrequency = [1/(2 pi)] sqrt (k/m)

0.93 = [1/(2 pi)] sqrt (k/m)

0.63 = [1/(2 pi)] sqrt [k/(m+0.607)]

Take the ratio. The k will cancel out.

0.93/0.63 = 1.476 = sqrt[(m+0.607)/m]

= sqrt (1 + 0.607/m )

2.179 = 1 + 0.607/m

1.170 = .607/m

Solve for m. It will be in kg since I wrote the added mass in kg

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