a bank teller had $2750 in 10 dollar bills and5 dollar bills he had twice as many10 dollar billsas 5 dollar bills how many of each bill does he have

let x = the number of $5 bills.

let y = the number of $10 bills.

"a bank teller had $2750 in 10 dollar bills and5 dollar bills"
5x + 10y = 2750

"he had twice as many 10 dollar bills as 5 dollar bills"
y = 2x

Solve for x and y. Substitution is likely easiest.

Let's assume the number of $5 bills the bank teller has is x.

According to the given information, the number of $10 bills the bank teller has is twice the number of $5 bills. Therefore, we can say the number of $10 bills is 2x.

The total value of all the $5 bills can be calculated as 5x.

Similarly, the total value of all the $10 bills can be calculated as 10(2x) = 20x.

We are given that the bank teller has a total of $2750. So, we can write the equation as:

5x + 20x = 2750

Simplifying the equation, we have:

25x = 2750

To solve for x, divide both sides of the equation by 25:

x = 2750/25

x = 110

Therefore, the bank teller has 110 $5 bills and 2(110) = 220 $10 bills.

To solve this problem, we need to set up equations based on the given information.

Let's assume the bank teller has x number of $5 bills.
According to the problem, the bank teller has twice as many $10 bills as $5 bills, so the number of $10 bills would be 2x.

Now, let's calculate the total value of the bills:
The value of each $5 bill is $5, so the total value of $5 bills would be 5x.
The value of each $10 bill is $10, so the total value of $10 bills would be 10(2x) = 20x.

According to the problem, the total value of all the bills is $2750. So we can set up the equation:

5x + 20x = 2750

Combine like terms:
25x = 2750

Divide both sides by 25 to solve for x:
x = 2750 / 25
x = 110

So, the bank teller has 110 $5 bills and twice as many $10 bills, which is 2 * 110 = 220 $10 bills.