Suppose that the allele for tallness (T) is dominant over shortness (t); that for Yellow (Y) is dominant over green (y); and that for roundness (W) is dominant over wrinkled (w). Suppose we cross two plants with genotypes TTYyWw and TtYyWw. The probability of a Tall, Yellow, Round plant is:
(a) 9/16
(b) 3/32
(c) 1/16
(d) 9/32
(e) 3/16
Using a Punnett square, all will be Tall with at least one T, 3/4 will be Yellow (with at least one Y gene) and 3/4 will be Round (with at least one W gene).
http://en.wikipedia.org/wiki/Punnett_square
The probability of all events occurring is found by multiplying the probability of the individual events.
I assume you can do the multiplication.
yes
To determine the probability of a specific genotype, we need to multiply the probabilities of each individual allele being passed on from the parents.
In this case, the genotype of the first parent is TTYyWw and the genotype of the second parent is TtYyWw.
Let's break down the probabilities for each allele:
For the allele for tallness (T):
- The first parent has two copies of the dominant allele (TT), so the probability of passing on a tall allele is 1.
- The second parent has one copy of the dominant allele (Tt), so the probability of passing on a tall allele is 1/2.
For the allele for yellow (Y):
- Both parents have one copy of the dominant allele (Y), so the probability of passing on a yellow allele is 1.
For the allele for roundness (W):
- The first parent has one copy of the dominant allele (W), so the probability of passing on a round allele is 1.
- The second parent has one copy of the dominant allele (W), so the probability of passing on a round allele is also 1.
Multiplying these probabilities together, we get:
(1) * (1/2) * (1) * (1) * (1) = 1/2
So, the probability of a Tall, Yellow, Round plant is 1/2.
Therefore, the correct answer is not provided among the options (a) 9/16, (b) 3/32, (c) 1/16, (d) 9/32, or (e) 3/16.