If the radius of curvature of the bump is r = 29 m, find the apparent weight of a 60 kg person in your car as you pass over the top of the bump at 12 m/s.

apparent weight= mg-mv^2/r

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To find the apparent weight of a person in the car as it passes over the bump, we need to consider the concept of apparent weight, which is the force experienced by an object in a non-inertial reference frame.

To calculate the apparent weight, we need to determine the net force acting on the person at the top of the bump, where the normal force and gravitational force combine.

To begin, let's break down the forces acting on the person at the top of the bump:

1. Gravitational Force (weight): The weight of the person is given by W = mg, where m is the mass of the person (60 kg) and g is the acceleration due to gravity (approximately 9.8 m/s²). So, the weight (gravitational force) is W = 60 kg * 9.8 m/s².

2. Normal Force: The normal force is the force exerted by a surface to support an object. At the top of the bump, the normal force should equal the weight plus the centripetal force required to keep the person moving in a circular path. Since the bump has a radius of curvature r = 29 m and the car is moving at a constant speed of 12 m/s, the centripetal force is given by Fc = m * (v² / r), where v is the speed of the car.

Now, to find the apparent weight:

1. Calculate the centripetal force:
Fc = 60 kg * (12 m/s)² / 29 m

2. Calculate the normal force:
Normal force (N) = Weight (W) + Centripetal force (Fc)
N = (60 kg * 9.8 m/s²) + (60 kg * (12 m/s)² / 29 m)

The sum of the weight and centripetal force will give you the net force, which represents the apparent weight.