Homework Help: Physics

Posted by Katy on Thursday, January 7, 2010 at 9:21pm.

Having landed on a newly discovered planet, an astronaut sets up a simple pedulum of length 1.29 m and finds that it makes 567 oscillations in 1020 s. The amplitude of the oscillations is very small compared to the pendulum's length.

What is the gravitational acceleration on the surface of this planet? (Answer in units of m/s squared)

Physics - drwls, Friday, January 8, 2010 at 8:05am
This is a duplicate post. I answered it yesterday.

Use the formula for the period:

P = 2 pi sqrt (L/g') and solve for g'

The period is 1020/567 s. Convert to decimal.
Physics - gfdg, Wednesday, February 10, 2010 at 7:14pm
dfgdfg

Answer this Question

Related Questions

Physics - Having landed on a newly discovered planet, an astronaut sets up a ...
phyiscs! - Having landed on a newly discovered planet, an astronaut sets up a ...
Physics - The acceleration of gravity at the surface of a newly discovered ...
Physics - The acceleration of gravity at the surface of a newly discovered ...
Physics - An astronaut takes a space trip to newly discovered palnet X. ...
Physics (Please Help) - An astronaut lands on an alien planet. He places a ...
Physics - Imagine you are an astronaut who has landed on another planet and ...
Physics - Imagine you are an astronaut who has landed on another planet and ...
Physics (Really need help with this) - An astronaut lands on an alien planet. He...
Physics - An astronaut on a distant planet wants to determine its acceleration ...

For Further Reading

First Name:
School Subject:
Answer: