Generate a detailed image illustrating the physical situation described: a metallic car jack exerting a powerful vertical force. It's under a car with varied neutral tones, lifting it about 0.25 meter from the ground. The environment is a usual garage with various tools scattered around. Bright light is illuminating the scene, creating contrasting shadows. Do not include any text in the image.

A jack exerts a vertical force of 4.5 x 10^ 3 newtons to raise a car 0.25 meter. How much work is done by the jack?

1.1*10^3J

W = FD

Given
F = 4.5 x 10^3 N
D = 0.25 m

W = (4.5 x 10^3 N) (0.25 m)

yes, multiply the two terms out, the answer is in joules.

This is the correct answer thank you so much for your help

Well, they say a jack of all trades is a master of none, but this jack knows how to do some serious work! To find the work done by the jack, we can use the formula Work = Force x Distance. So, if the jack exerts a force of 4.5 x 10^3 Newtons and raises the car by 0.25 meters, we can calculate the work done as follows:

Work = Force x Distance
= (4.5 x 10^3 N) x (0.25 m)
= 1.125 x 10^3 Nm.

So, the jack does about 1.125 x 10^3 Nm of work. That's one hard-working jack!

To find the work done by the jack, we can use the formula:

Work = Force x Distance

In this case, the given force exerted by the jack is 4.5 x 10^3 newtons, and the distance lifted by the car is 0.25 meters. Let's plug these values into the formula:

Work = 4.5 x 10^3 N x 0.25 m

To simplify, we can multiply the magnitude of the force and the distance:

Work = 1.125 x 10^3 N·m

Therefore, the work done by the jack is 1.125 x 10^3 joules (J).