i have a six digit question my 100 thousands is one less than my ones digit,eight greater than my thousands digit,twice my tens digit and four times my hundreds digit,my ten thousand digit is zero,what number am i

check it again but I am pretty sure it's 800,249

To solve this problem, we need to analyze the given information and apply some mathematical operations.

Let's break it down step by step:

1. The ten thousands digit is zero: This means that the number must start with a zero.

2. The hundred thousands digit is one less than the ones digit: Since the ones digit cannot be zero (as the ten thousands digit is zero), we can deduce that the hundred thousands digit must be one less than the ones digit.

3. Eight greater than the thousands digit: This implies that the thousands digit must be one less than (or eight less than in terms of absolute value) the hundred thousands digit.

4. Twice the tens digit: This means that the tens digit must be half of the hundred thousands digit.

5. Four times the hundreds digit: This implies that the hundreds digit must be one-fourth of the hundred thousands digit.

Now let's use this information to find the number:

Let's assume the number is ABCDEF. Breaking it down into each digit form, we have:

A B C D E F

- A = 0 (from the given information)
- F = A - 1 (hundred thousands digit is one less than ones digit)
- E = C - 8 (thousands digit is eight less than the hundred thousands digit)
- D = 2B (tens digit is twice the hundred thousands digit)
- C = 4D (hundreds digit is four times the hundred thousands digit)

Since we know A = 0, we can determine the following:

- E = C - 8 = 4D - 8 (substituting C and simplifying)
- D = 2B = 2(0) = 0 (tens digit is twice the hundred thousands digit)

Now substitute D = 0 into the equation for E:

- E = 4D - 8 = 4(0) - 8 = -8

However, a digit cannot be negative, so this combination of values is not possible. Therefore, there is no solution that satisfies all the given conditions.

Hence, we cannot determine the number based on the information provided.