Draw a ray diagram for an object 2 cm tall located 15 cm away from a concave mirror with a focal length of 5 cm on your own paper. Describe the image by saying if the image is real or imaginary, inverted or upright, and larger or smaller than the object. Also indicate if the magnification is more or less than 1.
I don't have a concave mirror pleeaasee heelppp!
The image is real, inverted, smaller and more than 1.
Is this right?
No worries, I can help you understand how to answer the question without physically having a concave mirror. To draw a ray diagram and analyze the image formed by a concave mirror, follow these steps:
1. Draw a straight horizontal line on your paper to represent the principal axis of the mirror.
2. Choose a point on the left side of the axis, where you will place the object. Mark this point as "O."
3. Draw a vertical line from point O, representing the object's height. In this case, the object is 2 cm tall.
4. Draw a dotted line perpendicular to the principal axis from point O. This line represents the path of the incident ray.
5. Draw a line from point O angled towards the mirror's focal point (F) on the principal axis. This line represents the reflected ray.
6. Draw a line from point O parallel to the principal axis. This line represents the central ray.
7. Extend the reflected ray behind the mirror. The point where the reflected ray intersects the incident ray (dotted line) is the location of the image. Mark this point as "I."
Now, let's analyze the image:
- If the image is formed in front of the mirror (on the same side as the object), it is a virtual or imaginary image. If the image is formed behind the mirror (opposite side of the object), it is a real image.
- If the image is inverted compared to the object, it is said to be inverted. If the image is the same orientation as the object, it is upright.
- To compare the size of the object and the image, measure the distance between point O and point I. If the image is smaller than the object, the image is reduced. If the image is larger than the object, the image is magnified.
- To determine the magnification, calculate the height of the image divided by the height of the object (hI / hO). If the magnification is greater than 1, it means the image is magnified. If the magnification is less than 1, it means the image is reduced.
Since I can't physically see your diagram, you'll need to make these observations and determine if the image is real or virtual, inverted or upright, larger or smaller than the object, and if the magnification is greater or less than 1 based on the ray diagram you drew on your paper.