Posted by Jose on Thursday, January 7, 2010 at 10:36am.
What is the temperature of the ice when you put it in?
heat to lose=100*specifheatwater*40
heat absorbed by ice: mass*specificheatice*(Ti)+ mass*Heatfusionice*(20)
set them equal, after putting in Tinitial of ice, and solve for the mass of ice.
the temperature of ice according to our physics teacher is -5 degrees celcius
Then
massice*(specificheatice)5+massice*heatfusionice*20= 100*spcificheatdwater*40
Related Questions
chemistry - if 27 grams of ice at 0 degrees celsius is added to 123 grams of ...
physics - what is the equilibrium temperature if 100 grams of water at 20 ...
General Chemistry II - A quantity of ice at 0 degrees celcius is added to 64.3 ...
Chemistry - At 50 degrees, 100 grams of water is saturated with cerium (III) ...
Physics - A cube of ice is taken from the freezer at -8.5 degrees celsius and ...
Physics - How much heat must be removed from 500 grams of water at 0 degrees C ...
Science - A 44 g piece of ice at 0 degrees celsius is added to a sample of water...
Chemistry - I've seen the posts on solving this particular equation, and I ...
AP Chemistry - The solubility of sodium nitrate is 32 grams in 50.0 grams of ...
AP Chemistry - The solubility of sodium nitrate is 32 grams in 50.0 grams of ...
For Further Reading