Posted by Andy on .
When an iceberg floats in the ocean, what fraction of it is visible?( The relative density of ice is 0.92, and the relative density of sea water is 1.03)

gr.11 physics help! 
drwls,
Use Archimedes' Principle.
Let the volume of the iceberg be V. The amount below water (V') must displace a weight of sea water equal to the weight of the iceberg.
seawater density x V' = ice density * V
1.03*V' = 0.92*V
V'/V = fraction below water = 0.89
Fraction above water = 1  V'/V = 0.11