Friday

November 21, 2014

November 21, 2014

Posted by **Andy** on Wednesday, January 6, 2010 at 10:52pm.

- gr.11 physics help! -
**drwls**, Wednesday, January 6, 2010 at 11:40pmUse Archimedes' Principle.

Let the volume of the iceberg be V. The amount below water (V') must displace a weight of sea water equal to the weight of the iceberg.

seawater density x V' = ice density * V

1.03*V' = 0.92*V

V'/V = fraction below water = 0.89

Fraction above water = 1 - V'/V = 0.11

**Answer this Question**

**Related Questions**

physics - A rectangular block of ice 8 m on each side and 1.5 m thick floats in ...

PHYSICS - The density of ice is 0.92g cm-3 & that of sea water is 1.025g cm-3....

Sandy - Hi, I need some help with this problem: The density of ice is 920 kg/m3...

PHYSICS - The density of ice is 0.92 g cm-3 & that of sea water is 1.025 g cm-3....

physics - A rectangular block of ice 10 m on each side and 1.1 m thick floats in...

Physics - a plastic duck floats half-immersedi n water in the bathtub. What ...

physics - A rectangular block of ice 10 m on each side and 1.1 m thick floats in...

Physics - what is the general relationship between the density of solids and the...

physics - The density of ice is 917 kg/m3, and the density of sea water is 1025 ...

Physics - density of ice 917 kg/m^3, density of sea water is 1025 kg/m^3, a ...