Posted by Anonymous on Wednesday, January 6, 2010 at 9:49pm.
of a^2+b^2=2ab, prove log[(a+b)/2]=1/2(loga+logb)
math - kayla, Wednesday, January 6, 2010 at 11:01pm
systems of equations by graphing
math - MathMate, Thursday, January 7, 2010 at 7:04am
I have made some editorial changes to reflect my interpretation of the question:
If a²+b²=2ab, then
(a-b)²=0 after factoring
So we conclude that a=b
Substituting a=b into the left-hand side of the equation:
The right-hand side:
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