Posted by Laila on Wednesday, January 6, 2010 at 9:48pm.
Let a be the speed acceleration rate. That vector will always be tangent to the circular path. There will also be a centripetal acceleration vector that increases with time. It is pointed toward the center of the circle and has magnitude V^2/R.
The time it takes to complete 5 revolutions is
T = 10 pi R/Vav = 20 pi R/V = V/a
where V is the speed at that time and Vav is the average speed during T, which is V/2.
Therefore V^2 = 20 pi R a
and
a(centripetal) = V^2/R
= 20 pi a(tangential)
The angle of the total acceleration vector to the radial direction is
arctan a(tangential)/a(centripetal) = arctan [1/(20 pi)] = 0.91 degrees
1/pi=4.55
Related Questions
Physics - A race car starts from rest on a circular track of radius 445 m. The ...
physics - A toy race car starts from rest on a circular track of radius 4.30 m. ...
physics - A toy race car starts from rest on a circular track of radius 4.30 m. ...
Physics - A race car starts from rest on a circular track of radius 500 m. The ...
Physics - A race car starts from rest on a circular track of radius 507 m. The ...
Physics HELP! - A toy race car starts from rest on a circular track of radius 4....
Physics- PLEASE HELP - A toy race car starts from rest on a circular track of ...
physics - 2 cars are in a race the first car is 200m ahead of the second car.the...
Math - A race car starts from rest on a circular track of radius 565 m. The car...
physics help please! - A race car is one lap behind the lead race car when the ...
For Further Reading