Posted by Anonymous on Wednesday, January 6, 2010 at 9:03pm.
I would write #1 as
Br2 + 2NaOH ==> NaOBr + NaBr + H2O
This is the balanced molecular equation.
Now convert to ions using the following rules.
solids written as molecules
liquids written as molecules
solutions written as ions unless they are weak electrolytes which are written as molecules.
Br2 + 2Na^+ + 2OH^- ==> NaOBr + Na^+ + Br^-^- + H2O
Now cancel ions common to both sides.
1Na^+ can be canceled on each side.
What is left is the net ionic equation.
Br2 + Na^+ + 2OH^- ==>NaOBr + Br^- + H2O
Check my thinking. Check my work.
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