Posted by SC on Wednesday, January 6, 2010 at 8:24pm.
If a ball is throw into the air with a velocity of 40ft/s its height in feet t seconds later is given by: y=40t16t^2. Find the average velocity for the time period beginning when t=2 and lasting 0.5 seconds.

Math  Marth, Wednesday, January 6, 2010 at 8:35pm
I assume the ball is thrown straight up, so the velocity only has 1 dimensional components.
The average velocity is the same as the average slope over the given time period.
m = (y1  y2) / (x1  x2)
average V = [y(2)  y(2.5)] / (2  2.5)

Math  SC, Wednesday, January 6, 2010 at 8:46pm
ohh i see it now! thank you!
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