Posted by Rach on Wednesday, January 6, 2010 at 7:11pm.
A diffraction grating gives a secondorder maximum at as angle of 31‹ for violet light (ƒÉ = 4.0 ~ 102 nm). If the diffraction grating is 1.0 cm in width, how many lines are on this diffraction grating?

physics  Rach, Wednesday, January 6, 2010 at 7:29pm
Sorry about the double post, and
the question is:
A diffraction grating gives a secondorder maximum at as angle of 31 degrees for violet light (wavelength = 4.0 x 102 nm). If the diffraction grating is 1.0 cm in width, how many lines are on this diffraction grating?

physics  bobpursley, Wednesday, January 6, 2010 at 7:49pm
n lambda = d sin( theta )
d=n * lambda/sinTheta
solve for d. That is the distance between slits, so lines/distance= 1/d
change wavelength to cm if you want lines per cm

physics  Rach, Wednesday, January 6, 2010 at 8:10pm
isn't that derived from the formula used for single slit though? and this is multiple slit (isn't that the same eqns as double slit?

physics  Rach, Wednesday, January 6, 2010 at 8:15pm
so n= 2 (second order)
theta= 31 degrees
d= 0.1 m
lambda= 4.0 x 10^7 m
(i'm required to solve in m)
is this correct?

physics  Anonymous, Saturday, June 2, 2012 at 2:23pm
no
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