Posted by **Rach** on Wednesday, January 6, 2010 at 7:11pm.

A diffraction grating gives a second-order maximum at as angle of 31‹ for violet light (ƒÉ = 4.0 ~ 102 nm). If the diffraction grating is 1.0 cm in width, how many lines are on this diffraction grating?

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**Rach**, Wednesday, January 6, 2010 at 7:29pm
Sorry about the double post, and

the question is:

A diffraction grating gives a second-order maximum at as angle of 31 degrees for violet light (wavelength = 4.0 x 102 nm). If the diffraction grating is 1.0 cm in width, how many lines are on this diffraction grating?

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**bobpursley**, Wednesday, January 6, 2010 at 7:49pm
n lambda = d sin( theta )

d=n * lambda/sinTheta

solve for d. That is the distance between slits, so lines/distance= 1/d

change wavelength to cm if you want lines per cm

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**Rach**, Wednesday, January 6, 2010 at 8:10pm
isn't that derived from the formula used for single slit though? and this is multiple slit (isn't that the same eqns as double slit?

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**Rach**, Wednesday, January 6, 2010 at 8:15pm
so n= 2 (second order)

theta= 31 degrees

d= 0.1 m

lambda= 4.0 x 10^-7 m

(i'm required to solve in m)

is this correct?

- physics -
**Anonymous**, Saturday, June 2, 2012 at 2:23pm
no

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