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August 30, 2014

August 30, 2014

Posted by **123university** on Tuesday, January 5, 2010 at 9:37pm.

y^2= 1/3, tan^2x = 1/3

yz= y, tan x sec x = tanx

- advanced functions -
**Reiny**, Tuesday, January 5, 2010 at 10:24pmy^2 = 1/3

y = ± 1/√3

so tan^2 x = 1/3

tanx = ± 1/√3

so x could be in all 4 quadrants

knowing the ratio of the 30-60-90 triangle is 1:√3:2

x must be 30º or pi/6 radians

so

x = pi/6 in I

x = pi - pi/6 = 5pi/6 in II

x = pi + pi/6 = 7pi/6 in III

x = 2pi - pi/6 = 11pi/6 in IV

for tan x sec x = tanx

divide by tanx

secx = 1

cosx = 1

Where is the cosine graph 1 ?

I will let you finish it.

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