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September 19, 2014

September 19, 2014

Posted by **Jennifer** on Tuesday, January 5, 2010 at 4:09pm.

Problem

7.)Tan(90-x)=-3/8

8.)Csc x=-13/5

9.)Cot x=square root of 3

10.)Sin(90-x)=-.4563

11.)Sec(-x)=4

12.)Cos x=-.2351

I need HELP!

- Trigonometry -
**Reiny**, Tuesday, January 5, 2010 at 4:29pmI will do one for you.

You try some of the others and let me know what you got.

#8

csc x = -13/5, then

sin x = -5/13

so by CAST, angle x is in either III or IV

construct a right-angled triangle with the side opposite angle x as 5 and hypotenuse 13 (sin ß = opp/hyp)

By Pythagoras the adjacent side is 12

so in III, (x is appr. 202.62º)

sin x = -5/13

cos x = -12/13

sec x = -13/12

tan x = 5/12

cot x = 12/5

in IV, (x is appr. 337.38º)

sin x = -5/13

cos x = 12/13

sec x = 13/12

tan x = -5/12

cot x = -12/5

- Trigonometry -
**Jennifer**, Tuesday, January 5, 2010 at 5:06pmWould #7 be Sin- 3 over square root of 73 Cos- 8 over square root of 73 Tan- -8/3 Csc- square root of 73 over 3 Cot- -3/8

- Trigonometry -
**basker**, Wednesday, November 30, 2011 at 12:24amsin x =4/5 and cos y = 5/3

sin x = 4/5

cos x = 3/5

soc^2 x = 5/3- answer

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