What potential energy does a 60.0-kg gymnast acquire in climbing 5.00 m up a vertical pole?
GIVEN:
mg = 60
h/d = 5.00 m
PE = mgh
PE = (60)(5.00)
PE = 300 J
no. mg=60kg*9.8N/kg
How did you get 9.8 N? Isn't 9.8 m/s^2 the acceleration?
gravitational potential energy = mgh
GPE = mass x gravity x height
GPE = 60 x 9.8 x 5
GPE = 2940
To calculate the potential energy acquired by the gymnast, you can use the equation PE = mgh, where PE is the potential energy, m is the mass of the gymnast, g is the acceleration due to gravity, and h is the height climbed.
In this given problem, the mass of the gymnast is 60.0 kg, and the height climbed is 5.00 m. The acceleration due to gravity, g, is approximately 9.8 m/s^2.
Now, substitute the given values into the equation:
PE = (60.0 kg)(9.8 m/s^2)(5.00 m)
Calculating this expression, we get:
PE = 300 J
Therefore, the potential energy acquired by the gymnast in climbing 5.00 m up the vertical pole is 300 Joules.