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July 23, 2014

July 23, 2014

Posted by **Anonymous** on Monday, January 4, 2010 at 4:17pm.

P(t)=300(1.05)^t

F(t)=1000(0.92)^t

- Advanced Functions -
**bobpursley**, Monday, January 4, 2010 at 4:28pm300(1.05)^t=1000(.92^t)

take the log of each side..

log 300+tlog1.05=log1000+tlog.92

t(log1.05-log.92)=log 1000-log300

t(log(1.05/.92)=log(1000/300)

t= log(920/315)=.465

check my math.

- Advanced Functions -
**Jonathan**, Thursday, January 24, 2013 at 11:50pmyou did it right up until:

t = log(920/314) = 0.465, I have no idea how you got those numbers but it's

t(log(1.05/.92))=log(1000/300)

t(log(1.1141304348)=log(3.3(rpt.))

t(0.057401472)=0.522878745

t=(0.522878745)/(0.057401472)

t=9.1092

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