physics electricity
posted by alex on .
An electric force moves a charge of +1.65 multiplied by 104 C from point A to point B and performs 6.40 multiplied by 103 J of work on the charge.
(a) What is the difference (EPEA  EPEB) between the electric potential energies of the charge at the two points?
(b) Determine the potential difference (VA  VB) between the two points.
(c) State which point is at the higher potential.

(a) Work done by the field is MINUS the change of potential energy.
So the EPE change is 6.40*10^3 J
Since they are asking for EPEA  EPAB, that is +6.40*10^3 J.
(b) Divide the previous answer by the charge, 1.64*10^4 C
(c) Point A has higher potential, since work was done on a positive charge going from A to B