Posted by Michael on Sunday, January 3, 2010 at 11:02pm.
(a) The horizontal range is
2 (Vo^2) sin 39 cos 39/g
= Vo^2 sin 78/g
= 2.584*10^5 m = 258.4 km
(b) The time in the air is
T = 2 Vo sin 39/g = 207 seconds
Related Questions
physics - A shell is fired from the ground with an initial speed of 1.54 103 m/s...
physics - A shell is fired from the ground with an initial speed of 1.58 103 m/s...
Physics - A shell is fired from the ground with an initial speed of 1.68 103 m/s...
physics - A shell is fired from the ground with an initial speed of 1.54 103 m/s...
Physics - A shell is fired from the ground with an initial speed of 1.72 103 m/s...
physics - A shell fired from the ground with an initial speed of 1.70 x 10^3 m/...
physics - An artillery shell is fired at an angle of 66.1 degrees above the ...
physics - An artillery shell is fired at an angle of 45.3◦ above the ...
physics - A cannon shell is fired up in the air at an initial speed of 225m/s. ...
PHYSICS! - A projectile is fired with an initial speed of 32.5 m/s at an angle ...
For Further Reading