Post a New Question


posted by on .

A shell is fired from the ground with an initial speed of 1.61 multiplied by 103 m/s at an initial angle of 39° to the horizontal.
(a) Neglecting air resistance, find the shell's horizontal range.

(b) Find the amount of time the shell is in motion.

For the first one I tried to find the horizantle component by using 1.6X10^3 Cos 39 and i got some huge number..

  • Physics - ,

    (a) The horizontal range is
    2 (Vo^2) sin 39 cos 39/g
    = Vo^2 sin 78/g
    = 2.584*10^5 m = 258.4 km

    (b) The time in the air is
    T = 2 Vo sin 39/g = 207 seconds

Answer This Question

First Name:
School Subject:

Related Questions

More Related Questions

Post a New Question