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December 18, 2014

December 18, 2014

Posted by **bob** on Sunday, January 3, 2010 at 10:32pm.

- calculus -
**drwls**, Monday, January 4, 2010 at 12:24amSince e^x = 1 + x + x^2/2! + x^3/3! + ...

e^2x = 1 + 2x + 4x^2/2! + 8x^3/3! + ...

It converges for all x.

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