Posted by **Kate** on Sunday, January 3, 2010 at 7:00pm.

h t t p : / / w w w . j i s k h a . c o m / d i s p l a y . c g i ? i d = 1 2 6 2 5 5 3 0 8 2

- Math -
**Kate**, Sunday, January 3, 2010 at 7:01pm
just in general

when I'm asked to sovle for X in a equation that is set to zero it's not really set to zero at all is it???

X^2 + 4X - 1 = 0

really what this is saying

X^2 + 4X - 1 = dy

right???

- Need more info -
**MathMate**, Sunday, January 3, 2010 at 8:38pm
The solution to

X^2 + 4X - 1 = 0

is

-2±√5

The equation is a quadratic in x.

If the equation is given as

X^2 + 4X - 1 = dx

it is missing something, because dx is a differential quantity while the left hand side is a full quantity.

Can you check your question and post again.

You can also help by telling to which course the question belongs, Calculus I, II or III or algebra.

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